MEDI11002 Physics for Health Sciences Assignment Sample

• Internal Code :
• Subject Code : MED11002
• University : CQ University
• Subject Name : Physics for health sciences

Question -1

1. The answer is false. The size of the force will decrease since by Coulomb's law the electric force between 2 charges is inversely proportional to the square of the distance between them.

2. The answer is true. This is true since gas flows from a region of higher pressure to a region of lower pressure.

no of moles n = PV/RT

here both are at same pressure, temperature ans volume

so they have same no of moles

therefore Both have same no of particles

since they have same no of moles

molecular weight of argon > molecular weight helium

mass of argon > mass of helium

since they have same volume

density = mass/volume

density of argon > desity of helium

3. The answer is false. This is false as the purpose of the ground plug is to complete the circuit path for high potential charges.

I assume that seperation is 1.3 centimeters

The potential difference between two vertical slots is,

V = Ed

Here, d is separation between two vertical slots.

Solve for E

E = V / d

E = 120 / 1.3 cm

E = 120 / 1.3*10^-2 m

E = 9200 V/m

4. The answer is false. False as by the mechanism of radiation also heat can be transferred between 2 objects.

1 calorie/gram °C = 4.186 joule/gram °C

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius

calorie = 4.18 Joule

specific heat of water is 4.186 kJ/kgC

200 mL = 0.1 kg

energy = 4.186 kJ/kgC x 0.1 kg x 60ºC = 25.1 kJ

energy = 4.186 kJ/kgC x 0.1 kg x 60ºC = 25.1 kJ

power = energy per unit time

100 J/s = 25.1 kJ / t

t = 251 seconds

5. The answer is false. False as the kinetic energy of an object depends on velocity and not on position.

kinetic energy K = 1/2 mv2

since speed is constant , the kinetic enrgy is also constant

answer : equal to one half of the mass times the linear speed's square

Question -2

1. Since, 

Pv = nRT, 

Vf = V/3, 

then 

Pf = 3P. 

So pressure increases by 3 times.

2. Since 

V = IR, 

Current in 10 ohm will be 3/2 times that in 15 ohm. 

Voltage across both resistances will be same.

3. Frequency of second from small bowl will be more than that from large bowl.

4. No both will have different. 

Copper is diamagnetic material so it is weakly magnetize in opposite direction to applied field. So when external field is removed bar B has large magnetic field in direction of applied field but bar A has weak field in opposite direction. 

four magnetic quadrupoles
two smaller bar magnets,i.e., two magnetic dipoles, each with a north pole and asouth pole
two isolatedmagnetic monopoles, a single north pole and a single southpole
two isolatedelectric charges, a positive charge and a negativecharge
This is atrick question because a magnetic dipole cannot be cut in half.